Answer:
- √5
Step-by-step explanation:
Given that, a ray intersects point (negative 3, 6) in quadrant 2 and we are told to find the value of secant theta.
To get the answer to the question,
The first step is to find the hypotenuse, we have to use the Pythagoras theorem where, Hypotenuse = opposite raise to power two + adjacent raise to power.
(I.e. h= O² + A²)
H = 6² + (-3)2
H = 36 + 9
H = 45
We then convert the answer to surds form.
H = 3√5
The next step is to find the value of secant theta.
To get the value of secant theta we will have to divide the hypotenuse by adjacent with a negative sign because of the negative sign in the second quadrant
We have
Sec ø = - (hypotenuse/adjacent)
Sec ø = - (3√5/ 3)
Sec ø = - √5
