Answer:
10cm, 19cm
Explanation:
Forgive me, I dont have a paper with me now so I cant show you the working BUT here's the rough idea...
Hooke's Law explains that the force needed to extend or compress a spring by some distance x scales linearly with respect to that distance. Take for example the picture above.
As such, the values can be placed in a linear graph, given that it goes not reach its elastic limit. So subtract 20g from 30g and you'll get 10g; subtract 16cm from 14cm makes it 2cm. Following hooke's law makes F=x, 2F=2x so 10g=2cm; 5g=1cm and 1g=0.2cm.
So, to find out how much was extended in the first figure, multiply 20g by 0.2 to get 4cm; the third figure, 30g by 0.2 to get 6cm.
Hence the answer to question one is 14-4 and 16-6 which is 10cm
Now knowing the original length, we can calculate x finding the extention. First, multiply 45g with 0.2 giving 9cm, then adding it to the original 10cm to obtain 19cm.
Hope this is understandable
