Answer:[tex]30^{\circ}[/tex]
Explanation:
Given
[tex]v_1=2 liter[/tex]
volume of water in bucket [tex]v_2=10 liter[/tex]
density of water [tex]\rho =1 kg/liter[/tex]
thus [tex]m_1=\rho \cdot v_1=2 kg[/tex]
[tex]m_2=\rho \cdot v_2=10 kg[/tex]
[tex]T_2=20^{\circ}C[/tex]
suppose [tex]T_1=80^{\circ}C[/tex]
Conserving heat energy i.e. heat lost by water is gained by water in bucket
[tex]m_1cT_1+m_2cT_2=(m_1+m_2)T[/tex]
where T=final Temperature
[tex]T=\frac{m_1T_1+m_2T_2}{m_1+m_2}[/tex]
[tex]T=\frac{160+200}{12}[/tex]
[tex]T=30^{\circ}C[/tex]
