Ribbon B is [tex]\frac{11}{15}[/tex] meters long
Solution:
Given that,
Ribbon A is 1/3 meter long. It is 2/5 meter shorter than ribbon B
To find: length of Ribbon B
From given information in question,
Length of Ribbon A = [tex]\frac{1}{3} \text{ meter }[/tex]
Length of Ribbon A is 2/5 meter shorter than ribbon B
Therefore we can say,
Length of Ribbon A = length of ribbon B - [tex]\frac{2}{5}[/tex]
[tex]\frac{1}{3} = \text{ length of ribbon B } -\frac{2}{5}\\\\\text{length of ribbon B } = \frac{1}{3} + \frac{2}{5}\\\\\text{length of ribbon B } = \frac{ 5 + 6}{15} = \frac{11}{15}[/tex]
Therefore ribbon B is [tex]\frac{11}{15}[/tex] meters long
