Answer:
613
Step-by-step explanation:
Given that
[tex]f(x)=4x^2-3x-1[/tex]
Substitute a+h for x
[tex]f(a+h)=4(a+h)^2-3(a+h)-1[/tex]
[tex]f(a)=4a^2-3a-1[/tex]
[tex]f(a+h)-f(a) = 4(a^2+2ah+h^2)-3(a+h)-1 - (4a^2-3a-1)\\= 8ah+4h^2-3h[/tex]
Divide by h and take limit as h tends to 0
we get
[tex]f'(x) = 8x-3[/tex]
c) Instantaneous rate of change
= f'(x)
when a = 77
we get
[tex]8(77)-3\\=613[/tex]