Answer:The margin of error is 0.01323 and 95% confidence interval is (0.674,0.73).
Step-by-step explanation:
Since we have given that
p = 0.70
n = 1200
We need to find the margin of error;
Margin of error would be
[tex]\sqrt{\dfrac{p(1-p)}{n}}\\\\=\sqrt{\dfrac{0.7\times 0.3}{1200}}\\\\=0.01323[/tex]
At 95% confidence level, α = 1.96
so, 95% confidence interval would be
[tex]p\pm z\times 0.01323\\\\=0.7\pm 1.96\times 0.01323\\\\=0.7\pm 0.02593\\\\=(0.7-0.02593,0.7+0.02593)\\\\=(0.674,0.73)[/tex]
Hence, the margin of error is 0.01323 and 95% confidence interval is (0.674,0.73).