Answer:
Δy = 1
dy = 1
Step-by-step explanation:
Data provided in the question:
dx = Δx
y = x
x = 1,
Δx = 1
Now,
we know,
Δy = f( x + Δx ) - f(x)
also, we have
y = f(x) = x
thus,
f( x + Δx ) = x + Δx
Therefore,
Δy = ( x + Δx ) - x
on substituting the respective values, we get
Δy = ( 1 + 1 ) - 1
or
Δy = 1
and,
dy = f'(x) = [tex]\frac{d(x)}{dx}[/tex]
or
dy = 1