For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis.
According to the statement data we have:
[tex]m = \frac {7} {3}[/tex]
Thus, the equation is of the form:
[tex]y = \frac {7} {3} x + b[/tex]
We substitute the given point and find the cut-off point:
[tex]- \frac {35} {3} = \frac {7} {3} (0) + b\\- \frac {35} {3} = b[/tex]
Finally, the equation is:
[tex]y = \frac {7} {3} x- \frac {35} {3}[/tex]
We manipulate algebraically to obtain the standard form:
We multiply by 3 on both sides of the equation:
[tex]3y = 7x-35\\3y-7x = -35[/tex]
We multiply by -1 on both sides:
[tex]7x-3y = 35[/tex]
Answer:
[tex]7x-3y = 35[/tex]
