Answer:
[tex]d < 20\ donuts[/tex]
The graph of the solution set in the attached figure
Step-by-step explanation:
Let
d ----> the possible number of donuts Monica brought
we know that
The number of donuts d multiplied by $0.50 plus the cost of a box of coffee for $5 must be less than $15
so
The inequality that represent this situation is
[tex]0.50d+5 < 15[/tex]
Solve for d
subtract 5 both sides
[tex]0.50d < 15-5[/tex]
[tex]0.50d < 10[/tex]
Divide by 0.50 both sides
[tex]d < 10/0.50[/tex]
[tex]d < 20\ donuts[/tex]
The solution is all whole numbers greater than zero and less than 20 ( I say greater than zero because the problem states that Monica brought some donuts)
The solution set is the interval {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19}
