Answer:
The lateral surface area of square pyramid is 448 square units.
Step-by-step explanation:
We are given the following in the question:
Side length of square pyramid = 11.2 units
Slant height of square pyramid = 20 units
Lateral area of a square pyramid =
[tex]L = \dfrac{1}{2}Ph[/tex]
where P is the perimeter of square base and h is the slant height.
Perimeter of square base =
[tex]P = 4\times \text{Base edge}\\= 4\times 11.2 = 44.8\text{ units}[/tex]
Putting the values, we get:
[tex]L = \dfrac{1}{2}\times 44.8\times 20 = 448\text{ square units}[/tex]
Thus, the lateral surface area of square pyramid is 448 square units.
Answer:
[tex]448 cm^{2}[/tex]
Step-by-step explanation:
s = 11.2; l = 20
L.A. = [tex]4 (\frac{1}{2} sl)[/tex]
L.A.= [tex]\frac{1}{2}(4 * 11.2)20[/tex] Multiply 4 * 11.2 to get perimeter 44.8
L.A. = [tex]\frac{1}{2} pl[/tex]
L.A. = [tex]\frac{1}{2} (44.8)20\\[/tex] Simplify 44.8 * 20
L.A. = [tex]\frac{1}{2}(896)\\[/tex] Divide 896 by 2
L.A. = [tex]448cm^{2}[/tex]
