Answer:
frequency of dominant and recessive alleles - 0.6, 0.4
frequency of individuals with dominant, Â heterozygous and recessive genotypes - 0.36, 0.48, 0.16
Explanation:
Given -
Short ears (S) is dominant over floppy ears.
Total population of rabbits [tex]= 653[/tex]
Population of rabbits with floppy ears [tex]= 104[/tex]
Population of rabbits with short ears [tex]= 549[/tex]
Frequency of rabbits with floppy ears is equal to
[tex]\frac{104}{653} \\= 0.159[/tex]
Thus as per Hardy weinberg's equation, frequency of recessive phenotype is represented by [tex]q^2\\[/tex]
Thus,
[tex]q^2 = 0.159 =0.16\\q = \sqrt{0.16} \\q = 0.4[/tex]
Thus,
[tex]p = 1-q\\p = 1-0.4\\p= 0.6[/tex]
Frequency of rabbits with short ears only
[tex]= p^ 2 \\= 0.6^2\\= 0.36\\[/tex]
Frequency of heterozygous rabbit (Ss)
[tex]p^2 + q^2 + 2pq = 1\\0.16 + 0.36 + 2pq = 1\\2pq = 1 - 0.36-0.16\\2pq = 0.48[/tex]