Answer:
neither
Step-by-step explanation:
(-3,1), (-7,-2)
Slope of the line containing point (-3,1), (-7,-2) is
[tex]slope = \frac{y_2-y_1}{x_2-x_1} =\frac{-2-1}{-7+3} =\frac{3}{4}[/tex]
Slope of the line containing point (2,-1), (8,4) is
[tex]slope = \frac{y_2-y_1}{x_2-x_1} =\frac{4+1}{8-2} =\frac{5}{6}[/tex]
Slope of both the lines are not same, so they are not parallel
the slope of both the lines are not negative reciprocal of one another
So they are not perpendicular
Hence they are neither parallel nor perpendicular.
