1. Set up a ratio:
7 tagged / 350 fish = 250 tagged / x fish
Solve for x:
x = (350 * 250) / 7
x = 12,500 fish
2. Divide number of boys by the population ratio:
450 / 2/5 = (450 *5) /2 = 2250 / 2 = 1125 total students.
3. 4 quarters = $1, so they have 24 quarters total.
The ratio 3:5 means for every 3 quarters there are 5 dimes.
24 quarters / 3 = 8
8 x 5 = 40 dimes.
(1) The population of fish in the False river is 12500.
(2) There are 1125 total number of students in the school .
(3) There are 40 dimes in the bag.
(1) Number of fish tagged by Louisiana biologists = 250
On the next day a sample was collected from the False river
The number of fish in the sample = 350
Number of tagged fish in the sample = 7
Let the population of fish in the False river = P
Takin the ratio we can
[tex]\rm \dfrac{7}{350}= \dfrac{250}{P} \\\\P = (250)(350)/(7)\\P = 12500[/tex]
So the population of fish in the False river = 12500
(2) The number of boys in the school = 450
Let the total number of students in the school be B
According to the given condition
[tex]\rm \dfrac{2}{5}\times B = 450\\\\B = (450\times 5) /2 \\B = 2250/2 =1125[/tex]
So the total number of students in the school = 1125
(3) Let the number of dimes in the bag be x
According to the given condition we can write
[tex]\rm \dfrac{Number\; of\; quarters }{Number\; of\; dimes } = \dfrac{3}{5} ........(1)[/tex]
Also it is given that there are $6 in quarters in the bag.
$1 = 4 quarters
So $6 has [tex]\rm 4\times 6 = 24 \; quarters[/tex]
So we can put this value in equation (1)
[tex]\dfrac{24}{x} =\dfrac{3}{5} \\\\x = 40 dimes[/tex]
So we can conclude that there are 40 dimes in the bag.
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