Answer:
[tex] y = \frac{dc-fa}{db-ea}[/tex]
[tex]x=\frac{c(db-ea)+b(fa-dc)}{a(db-ea)}[/tex]
Step-by-step explanation:
For any system of equations we can use the method of elimination in order to solve the system:
Let's assume the following system of equations:
[tex] ax +by = c[/tex] (1)
[tex] dx +ey =f[/tex] (2)
We need to follow these steps:
Part 1 :"Multiply each equation by a suitable number so that the two equations have the same leading coefficient".
For example we can multiply equation (1) by d and equation (2) by -a and we got this:
[tex] dax +dby = dc[/tex] (1)
[tex] -dax -eay =-fa[/tex] (2)
Part 2: Add the first and the second equation. And after do this we got:
[tex] dby -eay = dc-fa[/tex] (3)
Part 3: "Solve this new equation for y".
First we take common factor y on the right of the equation (3)
[tex] y(db-ea)=dc-fa[/tex]
[tex] y = \frac{dc-fa}{db-ea}[/tex]
Part 4: "Substitute the valu obtained of y into either Equation 1 or Equation 2 above and solve for x." We can use equation 1 for example and we got:
[tex] ax +b \frac{dc-fa}{db-ea} = c[/tex]
[tex] ax = c -\frac{b(dc-fa)}{db-ea}[/tex]
[tex] x= \frac{cdb -cea -bdc+bfa}{a(db-ea)}[/tex]
[tex]x=\frac{c(db-ea)+b(fa-dc)}{a(db-ea)}[/tex]
Answer:
Its the Adding a quantity one or the bottom right
