AlexGender25 AlexGender25

02-01-2020
Mathematics

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y= -1/2(x+10)^2+14 Find the range

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surjithayer10otahza surjithayer10otahza

02-01-2020

Answer:

Step-by-step explanation:

y=-1/2(x+10)^2+14

2y=-(x+10)^2+28

(x+10)^2=28-2y

L.H.S. is positive.

so 28-2y≥0

28≥2y

or 2y≤28

or y≤ 14

Range is (-∞,14]

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