Bi undergoes four decay reactions: α, β, β, α. Step 1. undergoes α decay to give In the second step, Tl-210 undergoes β decay. What is the product of this step? symbol = mass number = atomic number =

Respuesta :

Answer:

Pb-210 that lead-210 is the product of second step.

Explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of alpha decay :

[tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha[/tex]

Beta decay : In this process, a neutron is converted into a proton and an electron. In this decay, the atomic number is increased by 1 unit.

General representation of beta decay :

[tex]_Z^A\textrm{X}\rightarrow _{Z+1}^{A}Y+_{-1}^0e[/tex]

Step 1. Bi undergoes α decay;

[tex]_Z^A\textrm{X}\rightarrow _{81}^{210}Tl+_2^4\alpha[/tex]

81 = Z-2

Z = 83

210 = A - 4

A = 214

[tex]_{83}^{214}\textrm{X}\rightarrow _{81}^{210}Tl+_2^4\alpha[/tex]

Step 2: Tl-210 undergoes β decay:

[tex]_{81}^{210}\textrm{X}\rightarrow _{82}^{210}Pb+_{-1}^0e[/tex]

Pb-210 that lead-210 is the product of second step.