Answer:
The student has to weigh 7.9 ±0.1 grams
Explanation:
Density of acetone : 0.790 g/cm³
If the student has to measure 10.0 mL of acetone, he can weigh an specific mass.
Density of acetone = Mass of acetone / Volume of acetone
cm³ = mL
0.790 g/cm³ = Mass of acetone / 10 cm³
0.790 g/cm³ . 10cm³ = 7.9 g