Answer : The molar mass of catalase is, [tex]2.40\times 10^5g/mol[/tex]
Explanation :
Formula used :
[tex]\pi =CRT\\\\\pi=\frac{w}{M\times V}RT[/tex]
where,
[tex]\pi[/tex] = osmotic pressure = 0.745 torr = 0.000980 atm (1 atm = 760 torr)
C = concentration
R = solution constant = 0.0821 L.atm/mol.K
T = temperature = [tex]27^oC=273+27=300K[/tex]
w = mass of catalase = 10.03 g
M = molar mass of catalase = ?
V = volume of solution = 1.05 L
Now put all the given values in the above formula, we get:
[tex]0.000980atm=\frac{10.03g}{M\times 1.05L}\times (0.0821L.atm/mole.K)\times (300K)[/tex]
[tex]M=2.40\times 10^5g/mol[/tex]
Therefore, the molar mass of catalase is, [tex]2.40\times 10^5g/mol[/tex]
