Respuesta :

TheSpectre

Answer:

J would be the answer, my friend.

log2 (24/3) = log5 (x)

log(8)/log(2) = log(x)/log(5)

log(x) = [log(5)][3]

log(x) = log(5^3)

x = 5^3 = 125

Step-by-step explanation:

mathstudent55

Answer:

x = 125

Step-by-step explanation:

[tex] \log_2 24 - \log_2 3 = \log_5 x [/tex]

Use the rule of subtracting logs:

[tex] \log_b x - \log_b y = \log_b \dfrac{x}{y} [/tex]

[tex] \log_2 \dfrac{24}{3} = \log_5 x [/tex]

[tex] \log_2 8 = \log_5 x [/tex]

[tex] 3 = \log_5 x [/tex]

Use the definition of log:

[tex] \log_b x = y ~~\Longleftrightarrow ~~ b^y = x [/tex]

[tex] x = 5^3 [/tex]

[tex] x = 125 [/tex]

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