The work done on the crate is: 187,500.0 J
Explanation:
According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Therefore:
[tex]W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
where:
W is the work done
m is the mass of the object
v is the final speed
u is the initial speed
For the crate in this problem, we have:
m = 5,000 kg is the mass
u = 5.0 m/s is the initial speed
v = 10.0 m/s is the final speed
Substituting, we find the work done:
[tex]W=\frac{1}{2}(5000)(10)^2-\frac{1}{2}(5000)(5)^2=187,500.0 J[/tex]
Learn more about work:
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