Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive object; the ring has a diameter of about 18 light-years and an orbital speed of about 180 km/s. answers

Respuesta :

Answer:

The mass of the massive object at the center of the Milky Way galaxy is [tex]3.44\times10^{37}\ Kg[/tex]

Explanation:

Given that,

Diameter = 10 light year

Orbital speed = 180 km/s

Suppose determine the mass of the massive object at the center of the Milky Way galaxy.

Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.

We need to calculate the radius of the orbit

Using formula of radius

[tex]r=\dfrac{d}{2}[/tex]

[tex]r=\dfrac{15\times9.461\times10^{15}}{2}[/tex]

[tex]r=7.09\times10^{16}\ m[/tex]

We need to calculate the mass of the massive object at the center of the Milky Way galaxy

Using formula of mass

[tex]M=\dfrac{v^2r}{G}[/tex]

Put the value into the formula

[tex]M=\dfrac{(180\times10^3)^2\times7.09\times10^{16}}{6.67\times10^{-11}}[/tex]

[tex]M=3.44\times10^{37}\ Kg[/tex]

Hence, The mass of the massive object at the center of the Milky Way galaxy is [tex]3.44\times10^{37}\ Kg[/tex]

The mass of the massive object is equal to [tex]3.44*10^37Kg[/tex]

How to get to this result?

  • First, we have to calculate the radius. This will be done with the following equation:

[tex]r=\frac{d}{2} \\r= \frac{15*9.461*10^1^5}{2} = 7.09*10^1^6 m[/tex]

  • After that, we can calculate the mass of the object through the equation:

[tex]M= \frac{v^2*r}{g} \\M= \frac{(180*10^3)^2*7.09*10^1^6}{6.67*10^1^1} \\M= 3.44*10^3^7Kg[/tex]

Your question is incomplete. The part you forgot is "Determine the mass of the massive object at the center of the Milky Way galaxy. Give your answer in kilograms"

More information about mass in the link:

https://brainly.com/question/19694949