Answer is " A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters. "
Explanation:
The figure shows Velocity vs Time Graph.
At t1=0, u=10m/s
At t2=5, v=2m/s
Let's calculated the acceleration
[tex]a=\frac{v-u}{t2-t1}[/tex]
[tex]a=\frac{2-10}{5-0}[/tex]
[tex]a=\frac{-8}{5}[/tex]
The equation of distance is given by
[tex]d=ut+\frac{a}{2} t^{2}[/tex]
[tex]d=(10)t+\frac{\frac{-8}{5}}{2} t^{2}[/tex]
[tex]d=10t+\frac{-8}{10} t^{2}[/tex]
[tex]d=10t+\frac{-4}{5} t^{2}[/tex]
[tex]5d=50t-4t^{2}[/tex]
From here, You can plot the graph of above equation by taking several points.
When t=0,
[tex]5d=50(0)-4(0)^{2} = 0m[/tex]
When t=5,
[tex]5d=50(5)-4(5)^{2}[/tex]
[tex]5d=250-100[/tex]
[tex]5d=150[/tex]
[tex]d=30m[/tex]
Similarly,
When t= 3s d=22.8m
When t=4s d=27.2m
Figure shown is graph of Distance vs Time.
Thus, answer is " A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters. "
