Answer:
Angular acceleration will be [tex]18.84rad/sec^2[/tex]
Explanation:
We have given that mass m = 0.18 kg
Radius r = 0.32 m
Initial angular velocity [tex]\omega _i=0rev/sec[/tex]
And final angular velocity [tex]\omega _f=24rev/sec[/tex]
Time is given as t = 8 sec
From equation of motion
We know that [tex]\omega _f=\omega _i+\alpha t[/tex]
[tex]24=0+\alpha \times 8[/tex]
[tex]\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2[/tex]
So angular acceleration will be [tex]18.84rad/sec^2[/tex]
