Answer:
0.2158 N.
Explanation:
Given , The ball has diameter (d)=3.72 cm = 0.0372 m
radius(r) = d/2 = 1.86 cm = 0.0186 m
Average density= 0.0841 g/cm^3 = 84.1 kg/m^3
There are two forces acting on the ball.. i.e. The buoyancy force and weight of the ball.
The force required to completely submerged under water= Buoyancy force - Weight of ball
buoyancy force = volume×density of water×g
[tex]F_b= \frac{4}{3} \pi r^{3}dg[/tex]
[tex]=4.18\times(0.018)^3\times 1000\times9.8[/tex]
[ density of water = 1000 kg/m3]
=0.238 N
mass of ball = average density×Volume
=84.1×4.18×(0.018)^3
=0.0022262 kg
Weight of ball = mg = 0.00204×9.81 =0.02219 N
Required force = 0.238 - 0.02219 = 0.2158 N.
