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Young's double slit experiment is one of the classic tests for the wave nature of light. In an experiment using red light (λ = 641 nm) the second dark fringe on either side of the central maximum is θ = 4.4 degrees relative to the central bright fringe.
(a) Write an expression for the separation distance between the slits.

Respuesta :

Answer:

The separation distance between the slits is 16710.32 nm.

Explanation:

Given that,

Wavelength = 641 nm

Angle =4.4°

(a). We need to calculate the separation distance between the slits

Using formula of young's double slit

[tex]d\sin\theta=m\lambda[/tex]

[tex]d=\dfrac{m\lambda}{\sin\theta}[/tex]

Where, d = the separation distance between the slits

m = number of order

[tex]\lambda[/tex] =wavelength

Put the value into the formula

[tex]d=\dfrac{2\times641\times10^{-9}}{\sin4.4}[/tex]

[tex]d=0.00001671032\ m[/tex]

[tex]d=16710.32\ nm[/tex]

Hence, The separation distance between the slits is 16710.32 nm.

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