Answer:
The rotational inertia of the system is 1.8 kg.m².
(b) is correct option.
Explanation:
Given that,
Mass of disk = 7.0 kg
Radius = 0.65 m
Mass of clay = 2.1 kg
Distance = 0.41 m
We need to calculate the rotational inertia of the system
Using formula of rotational inertia
[tex]I''=I+I'[/tex]
Where, I= the moment of inertia of a solid disk
I'=the moment of inertia of lump of clay
Put the value into the formula
[tex]I=\dfrac{MR^2}{2}+mr^2[/tex]
[tex]I=\dfrac{1}{2}\times7.0\times(0.65)^2+2.1\times0.41^2[/tex]
[tex]I=1.8\ kg.m^2[/tex]
Hence, The rotational inertia of the system is 1.8 kg.m².
