contestada

Gas A has molecules with small mass. Gas B has molecules with larger mass. They are at the same temperature.
How do the gases compare with respect to the average translational kinetic energy?
a)A has a larger average kinetic energy.b)B has a larger average kinetic energy.c)The gases have the same average kinetic energy.

Respuesta :

Answer:

c)The gases have the same average kinetic energy.

Explanation:

As we know that the kinetic energy of gas is given as

[tex]K = \frac{1}{2}mv^2[/tex]

here we know that

[tex]v = \sqrt{\frac{3RT}{M}}[/tex]

so we have

[tex]K = \frac{1}{2}m (\frac{3RT}{M})[/tex]

now we have

[tex]K = \frac{3}{2}n RT[/tex]

now mean kinetic energy per molecule is given as

[tex]K_{avg} = \frac{3}{2}KT[/tex]

so this is independent of the mass of the gas

so average kinetic energy will remain same for both the gas molecules

Otras preguntas