Answer: 0.36
Step-by-step explanation:
Given : Sample size of spools of wire : n= 24
The sample variance = [tex]s^2=0.13[/tex]
The the sample standard deviation should be the square root of the sample variance.
i.e. Sample standard deviation = [tex]s=\sqrt{0.13}=0.360555127546approx0.36[/tex]
Also, the sample standard deviation(s) is the best estimate of population standard deviation [tex](\sigma)[/tex].
Therefore , a point estimate for the population standard deviation [tex](\sigma)[/tex] of the diameter of the spools of wire. =s= 0.36
Hence, a point estimate for the population standard deviation of the diameter of the spools of wire= 0.36
