The final velocity is 49.7 m/s downward
Explanation:
The motion of the object is a free fall motion (affected only by the force of gravity), so the object accelerates downward with a constant acceleration of [tex]g=9.8 m/s^2[/tex] (acceleration of gravity). Therefore, we can use the following suvat equation:
[tex]v^2 -u^2 = 2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
Taking downward as positive direction, we have
u = 11.0 m/s
[tex]a=g=9.8 m/s^2[/tex]
[tex]s=1.3\cdot 10^2 m = 130 m[/tex] (height of the building)
Solving for v, we find the final velocity as the object hits the ground:
[tex]v=\sqrt{u^2+2as}=\sqrt{11.0^2+2(9.8)(120)}=49.7 m/s[/tex]
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