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The length of a rectangle is 7 yd more than double the width, and the area of the rectangle is 99 yd^2. find the dimensions of the rectangle.

Respuesta :

Answer:

w(2w+7) = 99

 

2w^2 + 7w - 99 = 0

 

(  2w   -   11  )(w   +    9  ) = 0

 

w+9=0 results in negative measures

 

2w-11 = 0

 

2w = 11

 

w = 11/2 = 5.5

 

L = 2w + 7 = 18

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