The question is incomplete. The complete question is attached below.
Answer:
(a). AB = 16.4 in
(b) BC = 11.5 in
Step-by-step explanation:
From the rectangle ABCD shown below,
AB is the base of rectangle and CB is the altitude of the rectangle.
Given:
AC = 20 in
(a)
From triangle ABC,
Applying cosine ratio for angle 35°, we get:
[tex]\cos(35)=\frac{AB}{AC}\\AB=AC\times \cos(35)\\AB=20\times \cos(35)=16.38\approx 16.4\ in[/tex]
Therefore, AB = 16.4 in
(b)
Applying sine ratio for angle 35°, we get:
[tex]\sin(35)=\frac{CB}{AC}\\CB=AC\times \sin(35)\\AB=20\times \sin(35)=11.47\approx 11.5\ in[/tex]
Therefore, CB = 11.5 in