Respuesta :
Answer:19.34 miles
Explanation:
Given
First car travels with 32 mi/h
second travels with 54 mi/h
they leave at 2:00 Pm at 45
distance traveled by them is 0.5 hr
suppose First is traveling towards x axis and another travels 45 to it
Distance traveled by first car is [tex]32\times 0.5=16 miles[/tex]
Position vector of first car after 0.5 hr
[tex]\vec{r_1}=32\times 0.5(\cos (45)\hat{i})[/tex]
Position vector of second car after 0.5 hr
[tex]\vec{r_2}=54\times 0.5(\cos (45)\hat{i}+\sin (45)\hat{j})[/tex]
distance between them
[tex]\vec{r_{21}}=27(\cos (45)\hat{i}+\sin (45)\hat{j})-16(\cos (45)\hat{i})[/tex]
[tex]\vec{r_{21}}=3.09\hat{i}+27\hat{j}\sin (45)[/tex]
distance between them[tex]|\vec{r_{21}}|=19.34[/tex]
