Answer:
Part 1 : Figure show the graph of triangle
Part 2 : The area of triangle is 4 sqaure units
Step-by-step explanation:
Given points A(1, -3), B(3, -1) and C(5, -3) make triangle.
Part 1:
Figure show the graph of triangle with A(1, -3), B(3, -1) and C(5, -3) as vertices.
Part 2: Find the area of the triangle.
The area of triangle is given by A=[tex]\frac{(Base)(height)}{2}[/tex]
From figure, Take base as length of AC
Length of line is given by L=[tex]\sqrt{(X1-X2)^{2}+(Y1-Y2)^{2} }[/tex]
Now, Base = length of AC
Base =[tex]\sqrt{(X1-X2)^{2}+(Y1-Y2)^{2} }[/tex]
=[tex]\sqrt{(1-5)^{2}+((-3)-(-3))^{2}}[/tex]
=[tex]\sqrt{(-4)^{2}+(0)^{2}}[/tex]
=[tex]\sqrt{16}[/tex]
=4units
and Height as difference of y-component of point A and point B
Height = (y of component of point B)- (y of component of point A)
= (-1)- (-3)
= 2units
Therefore, The area of triangle is given by A=[tex]\frac{(Base)(height)}{2}[/tex]
A=[tex]\frac{(4)(2)}{2}[/tex]
A=4 sqaure units
