The number of adults was 52 and number of children was 88.
Step-by-step explanation:
Cost for one adult = $8
Cost for one child = $5
People attended = 140
Amount raised = $856
Let,
x be the number of adult
y be the number of children
According to given statement;
x+y=140 Eqn 1
8x+5y=856 Eqn 2
Multiplying Eqn 1 by 8'
[tex]8(x+y=140)\\8x+8y=1120\ \ \ Eqn\ 3\\[/tex]
Subtracting Eqn 2 from Eqn 3
[tex](8x+8y)-(8x+5y)=1120-856\\8x+8y-8x-5y=264\\3y=264[/tex]
Dividing both sides by 3
[tex]\frac{3y}{3}=\frac{264}{3}\\y=88[/tex]
Putting y=88 in Eqn 1;
[tex]x+88=140\\x=140-88\\x=52[/tex]
The number of adults was 52 and number of children was 88.
Keywords: linear equations, subtraction
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