Answer:[tex]a=1.75\times 10^{21}\left ( 2\hat{i}5.08\hat{j}\right )[/tex]
Explanation:
Given
Electric Field [tex]\vec{E}=2\hat{i}+5.4\hat{j}[/tex]
[tex]\vec{B}=0.4\hat{k}\ T[/tex]
velocity [tex]\vec{v}=8\hat{i} m/s[/tex]
mass of electron [tex]m=9.1\times 10^{-31} kg[/tex]
Force on a charge Particle moving in Magnetic Field
[tex]F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ][/tex]
[tex]a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}[/tex]
[tex]a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}[/tex]
[tex]a=1.75\times 10^{21}\left ( 2\hat{i}+5.08\hat{j}\right )\ m/s^2[/tex]
