Answer: z=1.9065
Step-by-step explanation:
As per given , we have
[tex]H_0: p=0.10\\\\ H_a: p<0.10[/tex]
Sample size : n= 150
No. of potatoes sampled are found to have major defects = 8
The sample proportion of potatoes sampled are found to have major defects :
[tex]\hat{p}=\dfrac{8}{150}=0.0533[/tex]
The test statistic for population proportion is given by :-
[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\ [/tex] , where p=population proportion.
n= sample size.
[tex]\hat{p}[/tex] = sample proportion.
[tex]z=\dfrac{0.0533-0.10}{\sqrt{\dfrac{0.10\times0.90}{150}}}\\\\=\dfrac{-0.0467}{0.02449}\\\\=-1.90651951647\approx1.9065[/tex]
Hence, the value of the large-sample z test statistic is z=1.9065 .