Respuesta :
Answer:
[tex]\theta_{min} = 1.21 \times 10^{-5}\ rad[/tex]
Explanation:
given,
diameter of the beam (d)= 5.85 cm
= 0.0585 m
average wavelength of the(λ) = 580 n m
angle of of spreading = ?
according to the Rayleigh Criterion the minimum angular spreading, for a circular aperture, is
[tex]\theta_{min} = 1.22\ \dfrac{\lambda}{d}[/tex]
[tex]\theta_{min} = 1.22\ \dfrac{580 \times 10^{-9}}{0.0585}[/tex]
[tex]\theta_{min} = 1.22\times 9.145 \times 10^{-6}[/tex]
[tex]\theta_{min} = 1.21 \times 10^{-5}\ rad[/tex]
the minimum angle of spreading is [tex]\theta_{min} = 1.21 \times 10^{-5}\ rad[/tex]
