Answer:
LCD = 30
Step-by-step explanation:
[tex]LCD\ of\ \dfrac{2}{3}\ and\ \dfrac{1}{6}\ is\ 6:\\\\\dfrac{2}{3}=\dfrac{2\cdot2}{3\cdot2}=\dfrac{4}{6}\\\\LCD\ of\ \dfrac{1}{6}\ ond\ \dfrac{11}{5}\ is\ 30:\\\\\dfrac{11}{5}=\dfrac{(11)(6)}{(5)(6)}=\dfrac{66}{30}\\\\\dfrac{1}{6}=\dfrac{(1)(5)}{(6)(5)}=\dfrac{5}{30}\\\\\dfrac{2}{3}=\dfrac{4}{6}=\dfrac{(4)(5)}{(6)(5)}=\dfrac{20}{30}\\\\\text{Therefore:}\\\\\dfrac{11}{5}+\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{66}{30}+\dfrac{20}{30}+\dfrac{5}{30}=\dfrac{66+20+5}{30}=\dfrac{91}{30}=3\dfrac{1}{30}[/tex]
