If the surface temperature of that person's skin is 30∘C (that's a little lower than healthy internal body temperature because your skin is usually a little colder than your insides), what is the total power that person will radiate? For now, assume the person is a perfect blackbody (so ϵ=1).

Respuesta :

Answer:

[tex]E=477.92\ W.m^{-2}[/tex]

Explanation:

Given that:

Absolute temperature of the body, [tex]T=273+30=303\ K[/tex]

  • emissivity of the body, [tex]\epsilon=1[/tex]

Using Stefan Boltzmann Law of thermal radiation:

[tex]E=\epsilon. \sigma.T^4[/tex]

where:

[tex]\sigma =5.67\times 10^{-8}\ W.m^{-2}.K^{-4}[/tex]   (Stefan Boltzmann constant)

Now putting the respective values:

[tex]E=1\times 5.67\times 10^{-8}\times 303^4[/tex]

[tex]E=477.92\ W.m^{-2}[/tex]