Colorium is an autosomal dominant trait in Nutonian flies (identical to earth fruit flies in every way). There are two alleles at this locus:F = Dominant allele; flies with this allele cannot observe the color Fuschia; these flies have the Colorium phenotype.+ = Wild type allele; flies who are homozygous for this allele can observe the color Fuschia; these flies do not have the Colorium phenotype.A cross of a true breeding male with Colorium and a true breeding female without Colorium produces F1 offspring that all have the Colorium phenotype. When a complementation cross is performed (with true breeding flies), we expect the following results: A. Half of the F1 offspring will have the Colorium phenotype.B. None of the F1 offspring will have the Colorium phenotype.C. All the F1 offspring will have the Colorium phenotype.D. Half of the female F1 offspring will have the Colorium phenotype.E. Only Fuschia-colored Nutonian flies will have the Colorium phenotype.

Question

02-12-2019
Biology

contestada

Colorium is an autosomal dominant trait in Nutonian flies (identical to earth fruit flies in every way). There are two alleles at this locus:F = Dominant allele; flies with this allele cannot observe the color Fuschia; these flies have the Colorium phenotype.+ = Wild type allele; flies who are homozygous for this allele can observe the color Fuschia; these flies do not have the Colorium phenotype.A cross of a true breeding male with Colorium and a true breeding female without Colorium produces F1 offspring that all have the Colorium phenotype. When a complementation cross is performed (with true breeding flies), we expect the following results: A. Half of the F1 offspring will have the Colorium phenotype.B. None of the F1 offspring will have the Colorium phenotype.C. All the F1 offspring will have the Colorium phenotype.D. Half of the female F1 offspring will have the Colorium phenotype.E. Only Fuschia-colored Nutonian flies will have the Colorium phenotype.

Respuesta :

Otras preguntas

In a recent year, the annual salary of the Governor of New York was $179,000. During the same year, the annual salary of the Governor of Tennessee was $94,000 l

Put these sentences into indirect speech

Does anyone think darcy and stacy are attractive.

Risks for chronic disease can be reduced by participating in moderate physical activity for a minimum of

Which Equation represents a line which is parallel to the line x-7y=-21?

aiko comes from a family whose members routinely live to be older than 100 years of age. it can be theorized that the centenarians in her family

Draw the structures of methyl oleate and propylene glycol. Which one is more polar, and how can you tell

do think it’s possible for two teenagers to fall in love at first sign?. Why or why not?. Do you think love at first sight is possible for anyone why and expla

Which is the rationalized form of the expression sqrtx/sqrtx+sqrt5

n+n²-n⁴+n²-y⁴I need the value of x in factorise form someone please help

ajeigbeibraheem ajeigbeibraheem · Answer 1 · 2019-12-06T00:05:16+01:00

Answer:

Half of the F1 offspring will have the Colorium phenotype

Explanation:

The Colorium has an autosomal dominant trait, so we can say the genotype of colorium phenotype is either OO or Oo and the non-colorium is oo.

In the initial cross(F1), the cross between male with colorium (OO or Oo) and female without colorium (oo) will be:

Let use the cross between Oo × oo

we will have: Oo, Oo, oo, oo (check the document below to view the punnet square of the cross)

From the results above, only half of the individuals get colorium, but in the question it is stated that the breeding produces F1 offspring that all have the Colorium phenotype.

Let's look at another cross between OO × oo

we will have: Oo,Oo,Oo,Oo (check the document below to view the punnet square of the cross)

From the above cross, all the F1 generation having colorium phenotype.

This implies that the genotype of colorium phenotype is OO

True breeding implies that the parents are homozygous and not heterozygous . As such If we make a complementation cross with true breeding flies.(i.e a true breeding female without Colorium) and the product of the F1 Ggeneration, we wil have:

the complementary cross between Oo × oo

which are: Oo,Oo,oo,oo (check the document below to view the punnet square of the cross)

Therefore, we conclude that Half of the F1 offspring will have the Colorium phenotype