Answer:
277.16 K is the temperature of the gas.
Explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas = [tex]1.10\times 10^5 Pa[/tex]
V = Volume of gas = [tex]5600 m^3[/tex]
n = number of moles of gas = [tex]\frac{1,070 kg}{4.00260 g/mol}=\frac{1,070,000 g}{4.00260 g/mol}=267,326.24 mol[/tex]
R = Gas constant = 8.314 J/mol.K
T = Temperature of gas = ?
Putting values in above equation, we get:
[tex]T=\frac{PV}{RT}[/tex]
[tex]T=\frac{1.10\times 10^5 Pa\times 5,600 m^3}{267,326.24 mol\times 8.314 J/mol K}[/tex]
T = 277.16 K
277.16 K is the temperature of the gas.