Answer:
λ = 547.96 nm
Explanation:
given,
thickness of soap bubble = 103 nm
refractive index of thin film = 1.33
using formula of constructive interference
[tex]2 n t = (m + \dfrac{1}{2})\times \lambda[/tex]
t is thickness of the medium
n is refractive index
m = 0,1,2...
now,
[tex]2 n t = (m + 0.5)\times \lambda[/tex]
at m = 0
[tex]2\times 1.33 \times 103 =0.5\times \lambda[/tex]
λ = 547.96 nm
at m = 1
[tex]2 n t = (m + 0.5)\times \lambda[/tex]
[tex]2\times 1.33 \times 103 =1.5\times \lambda[/tex]
λ = 182.65 nm
the only visible light enhanced by the thin film is of wavelength
λ = 547.96 nm
