The work done on the block is B) 400 J
Explanation:
The work done when lifting an object is equal to the change in gravitational potential energy of the object:
[tex]W=mg \Delta h[/tex]
where
m is the mass of the object
g is the acceleration of gravity
[tex]\Delta h[/tex] is the change in height of the object
In this problem we have:
(mg) = 100 N is the weight of the block (product of mass and acceleration of gravity)
[tex]\Delta h = 6 m - 2 m = 4 m[/tex] is the change in heigth of the object
Substituting, we find the work done:
[tex]W=(100)(4)=400 J[/tex]
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