Answer:
Velocity of the first car after the collision, [tex]v_1=8.93\ m/s[/tex]
Explanation:
It is given that,
Mass of the car, [tex]m_1 = 480\ kg[/tex]
Initial speed of the car, [tex]u_1 = 14.4\ m/s[/tex]
Mass of another car, [tex]m_2 = 570\ kg[/tex]
Initial speed of the second car, [tex]u_2 = 13.3\ m/s[/tex]
New speed of the second car, [tex]v_2 = 17.9\ m/s[/tex]
Let [tex]v_1[/tex] is the final speed of the first car after the collision. The total momentum of the system remains conserved, Using the conservation of momentum to find it as :
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
[tex]m_1u_1+m_2u_2-m_2v_2=m_1v_1[/tex]
[tex]480\times 14.4+570\times 13.3-570\times 17.9=480v_1[/tex]
[tex]v_1=8.93\ m/s[/tex]
So, the velocity of the first car after the collision is 8.93 m/s. Hence, this is the required solution.
