Step-by-step explanation:
You have the equation of a line in the point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point on a line
Convert the given equation to the slope-intercept form:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept (0, b)
[tex]y+1=\dfrac{1}{3}(x-3)[/tex] use the distributive property
[tex]y+1=\dfrac{1}{3}x-1[/tex] subtract 1 from both sides
[tex]y=\dfrac{1}{3}x-2[/tex]
We only need two points to draw the line.
Choose two different x values. Put them in the line equation and calculate the y values:
for x = 0:
[tex]y=\dfrac{1}{3}(0)-2=0-2=-2\to(0,\ -2)[/tex]
for x = 3:
[tex]y=\dfrac{1}{3}(3)-2=1-2=-1\to(3,\ -1)[/tex]
