Respuesta :

SvetkaChem

Answer:

5.603 g H2

Step-by-step explanation:

 M(NH3) = 14 + 1*3 = 17 g/mol

M(H2) = 2*1 = 2 g/mol

                        3H2 + N2 ----->   2NH3

from reaction   3 mol                  2 mol

from reaction    3*2 g                  2*17 g

given                    x g                   31.75 g

We can write a proportion.

(3*2)/x = 2*17/31.75

(2*17)x = (3*2)*31.75

x = (3*2)*31.75/(2*17) = 3*31.75/17 =5.603 g H2

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