Answer:
65.712 grams of oxygen has reacted.
Explanation:
[tex]2 C_2H_2(g) + 5 O_2(g)\rightarrow 4 CO_2(g) + 2 H_2O(g)[/tex]
Mass of acetylene = 21.39 g
Moles of acetylene = [tex]\frac{21.39 g}{26.04 g/mol}=0.8214 mol[/tex]
According to reaction , 2 moles of acetylene reacts with 5 moles of oxygen gas.
Then 0.8214 moles of oxygen gas will react with :
[tex]\frac{5}{2}\times 0.8214 mol=2.0535 mol[/tex] of oxygen gas.
Mass of 2.0535 moles of oxygen gas :
2.0535 mol × 32 g/mol = 65.712 g
65.712 grams of oxygen has reacted.
