A block of mass 2.20 kg is placed against a horizontal spring of constant k = 825 N/m and pushed so the spring compresses by 0.0650 m. HINT (a) What is the elastic potential energy of the block-spring system (in J)?

Respuesta :

Answer:1.742 J

Explanation:

Given

mass of block [tex]m=2.2 kg[/tex]

[tex]k=825 N/m[/tex]

Compression in spring [tex]x=0.065 m[/tex]

Elastic Potential Energy of the Spring-mass system is given by

[tex]E=\frac{1}{2}kx^2[/tex]

where [tex]k=spring\ constant[/tex]

[tex]x=compression\ in\ spring[/tex]

[tex]E=\frac{1}{2}\times 825\times (0.065)^2[/tex]

[tex]E=412.5\times 42.25\times 10^{-4}[/tex]

[tex]E=1.742 J[/tex]