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A student sees her physical science professor approaching on the sidewalk that runs by her dorm. She gets a water balloon and waits. When the professor is 2 s from being directly under her window 11 m above the idewalk, she drops the balloon. You finish the story. (Assume g # 10 m/s*)

Respuesta :

Answer:Misses the Target

Explanation:

Given

Distance between window and Professor is h=11 m

she dropped the balloon 2 sec earlier

time taken by balloon to cover the 11  m

using

[tex]h=ut+\frac{at^2}{2}[/tex]

where h=height

u=initial velocity

t=time

a=acceleration

[tex]11=0+\frac{9.8t^2}{2}[/tex]

[tex]t=\sqrt{\frac{2\times 11}{10}}[/tex]

[tex]t=\sqrt{2.2}[/tex]

[tex]t=1.483 s[/tex]

Therefore she misses the Professor by 0.51 s