Answer:
The height of the bag will be 0.133 m
Explanation:
We have given gauge pressure [tex]P=1.33\times 10^3Pa=1330Pa[/tex]
Density of solution [tex]\rho =1.02\times 10^3=1020kg/m^3[/tex]
We have to find the height of the bag
We know that gauge pressure is given by P=\rho gh
[tex]1330=1020\times 9.8\times h[/tex]
h=0.133m
So the height of the bag will be 0.133 m